sederhanakan ( a² b³ -² / a⁴ b-⁴c⁶ )²
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Materi : Bentuk Akar dan Pangkat
( a²b³-²/a⁴b-⁴c⁶ )²
= a⁴b²/a⁸b-⁸c¹²
= ( 1/a⁸-⁴ )( b²-[-⁸] )( 1/c¹²-² )
= ( 1/a⁴ )( b¹⁰ )( 1/c¹⁰ )
= b¹⁰/a⁴c¹⁰
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
[tex]( \frac{ {a}^{2} b {}^{3} c {}^{ - 2} }{a {}^{4} b {}^{ - 4} c {}^{6} } ) {}^{2} = ( \frac{a {}^{4}b {}^{6} c {}^{ - 4} }{ {a}^{8} b {}^{ - 8}c {}^{12} }) [/tex]
[tex] = {a}^{ - 4} b {}^{16} c {}^{ - 16} [/tex]
[tex] = a. b {}^{ - 4} .c {}^{4} [/tex]
#semangatbelajar
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